count and print the total number and sum of odd and even number in the array .

 



#include<stdio.h>
#include<conio.h>
 main()
{
    int a[100],sum=0,i,n;
    int evencount=0,oddcount=0,sum1=0,sum2=0;
    
    printf("enter the size of array ");
    scanf(" %d",&n);
    printf("enter the numbers ");
    for(i=0;i<n;i++)
{
    scanf("%d",&a[i]);
}
     for(i=0;i<n;i++)
{
         sum=sum+a[i];
}
    printf("sum of all numbers is  %d\n",sum);
     for (i=0;i<n;i++)
{
     if (a[i]%2 == 0)
    { evencount++;
         sum1=sum1+a[i];    }

     if (a[i]%2 != 0)
    { oddcount++;
        sum2=sum2+a[i];      }
}
     printf("\n the sum of all even numbers is %d",sum1);

     printf("\n the sum of all odd numbers is %d",sum2);

     printf("\n total even array elements : %d",evencount);

     printf("\n total odd array elements : %d",oddcount);


    return 0;

}

output :

enter the size of array 9 enter the numbers 23 45 22 12 34 23 7 4 5 sum of all numbers is 175 the sum of all even numbers is 72 the sum of all odd numbers is 103 total even array elements : 4 total odd array elements : 5


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