Count and print total number of positive, negative numbers and zero in array

 


#include<stdio.h>
main()
{
  int   a[100],n,i,size,posi,zcount=0,pcount=0,ncount=0;

  printf("enter the size of an array ");
  scanf("%d",&n);

  printf("enter the elements of array :\n");
  for ( i = 0; i < n; i++)
  {
    scanf("%d",&a[i]);
  }
  
  for ( i = 0; i < n; i++)
  {
      if (a[i]==0)
      {
          zcount=zcount+1;
      }

      else if (a[i]<0)
      {
         ncount=ncount+1;
      }

      else
      {
          pcount=pcount +1;
      }
      
  }
  
 printf("there are %d zero numbers in the array \n ",zcount );
 
 printf("there are %d positive numbers in the array \n ",pcount );
  
 printf("there are %d negative numbers in the array \n ",ncount );


 return 0;

}

output :
enter the size of an array 9 enter the elements of array : 2 4 0 0 5 -4 -6 -9 7
there are 2 zero numbers in the array
there are 4 positive numbers in the array
there are 3 negative numbers in the array

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