Input a number and search that number in a list of 10 elements. If it is found print message “Number is found” otherwise print message “Number is not found”.

 

#include<stdio.h>

#include<conio.h>

 main()

{

           int a[100],i,n,number ,c;


 printf("enter the size of an array ");

 scanf("%d",&n);


        for(i=0;i<n;i++)

        { 

               printf("enter the number ");

               scanf("%d",&a[i]);

         }

  

          for(i=0;i<n;i++)

          { 

                 printf("\nvalue of array is %d",a[i]);

          } 

 

  printf("\nfind no.");

  scanf("%d",&number );

 

         for(i=0;i<n;i++)

         {

                if(a[i]==number)

                    { 

                         printf("\nno. found ");

                         break;

                     } 

         }


                  if(i==n)

                   printf("\nno not found ");


getch ();


}

Output 1 :

enter the size of an array 5

enter the number 23

enter the number 45

enter the number 67

enter the number 54

enter the number 98


value of array is 23

value of array is 45

value of array is 67

value of array is 54

value of array is 98


find no.45


no. found


[Process completed - press Enter]


Output 2:

enter the size of an array 3

enter the number 34

enter the number 56

enter the number 65


value of array is 34

value of array is 56

value of array is 65


find no.8


no not found


[Process completed - press Enter]



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