Wap to find a number position in array
#include<stdio.h>
#include<conio.h>
main()
{
int a[100],i,n,number ,c;
printf("enter the size of an array ");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("enter the number : ");
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
{
printf("\nvalue of array is %d",a[i]);
}
printf("\nfind no.");
scanf("%d",&number );
for(i=0;i<n;i++)
{
if(a[i]==number)
{ printf("\n%d no. is found at %dposition",number,i+1);
break;
}
}
if(a[i]!=number)
printf("\nno. not found ");
getch ();
}
Output 1 :
enter the size of an array 6
enter the number : 23
enter the number : 45
enter the number : 43
enter the number : 87
enter the number : 89
enter the number : 76
value of array is 23
value of array is 45
value of array is 43
value of array is 87
value of array is 89
value of array is 76
find no.87
87 no. is found at 4 position
[Process completed - press Enter]
Output 2 :
enter the size of an array 4
enter the number : 23
enter the number : 45
enter the number : 43
enter the number : 98
value of array is 23
value of array is 45
value of array is 43
value of array is 98
find no.56
no. not found
[Process completed - press Enter]
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