Wap to find a number position in array

 


#include<stdio.h>

#include<conio.h>

main()

{

            int a[100],i,n,number ,c;


 printf("enter the size of an array ");

 scanf("%d",&n);


       for(i=0;i<n;i++)

      { 

              printf("enter the number : ");

              scanf("%d",&a[i]);

      }


      for(i=0;i<n;i++)

      {

              printf("\nvalue of array is %d",a[i]);

      }


  printf("\nfind no.");

  scanf("%d",&number );

 

       for(i=0;i<n;i++)

       {

               if(a[i]==number)

                   { printf("\n%d no. is found at %dposition",number,i+1);

                      break;

                   }   

       }


                 if(a[i]!=number)

                 printf("\nno. not found ");


  getch ();


}


Output  1 :


enter the size of an array 6

enter the number : 23

enter the number : 45

enter the number : 43

enter the number : 87

enter the number : 89

enter the number : 76


value of array is 23

value of array is 45

value of array is 43

value of array is 87

value of array is 89

value of array is 76


find no.87


87 no. is found at 4 position


[Process completed - press Enter]


Output 2 :


enter the size of an array 4

enter the number : 23

enter the number : 45

enter the number : 43

enter the number : 98


value of array is 23

value of array is 45

value of array is 43

value of array is 98


find no.56


no. not found


[Process completed - press Enter]


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